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x=25x^2-30x+9
We move all terms to the left:
x-(25x^2-30x+9)=0
We get rid of parentheses
-25x^2+x+30x-9=0
We add all the numbers together, and all the variables
-25x^2+31x-9=0
a = -25; b = 31; c = -9;
Δ = b2-4ac
Δ = 312-4·(-25)·(-9)
Δ = 61
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(31)-\sqrt{61}}{2*-25}=\frac{-31-\sqrt{61}}{-50} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(31)+\sqrt{61}}{2*-25}=\frac{-31+\sqrt{61}}{-50} $
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